4(x^2)+36x+77=0

Solution for 4(x^2)+36x+77=0 equation:

4(x^2)+36x+77=0

a = 4; b = 36; c = +77;
Δ = b2-4ac
Δ = 362-4·4·77
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-8}{2*4}=\frac{-44}{8}
=-5+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+8}{2*4}=\frac{-28}{8}
=-3+1/2
$